[Phys-L] Re: projectiles

[kphox at CHERRYCREEKSCHOOLS.ORG (SSHS KPHOX)]

Forum for Physics Educators <PHYS-L@list1.ucc.nau.edu> writes:
> It is true that v^2/(g*h) diverges as h --> 0, but the relevant
> quantity is 1/(1 + v^2/(g*h)) = g*h/(g*h + v^2) --> 0 as h --> 0 and
> (1/2)*arcos(0) =
(1/2)
> [pi]/2 rad = 45 deg.

Thanks for the correction elucidation and follow up addition of the 1/2. I
should have known enough put the g*h in the numerator.

 I have officially made my last public mistake of 2004. ;-)

Ken Fox