[Phys-L] Re: projectiles

[msylvest at XNET.IT (Mark Sylvester)]

A formula is easy enough to derive... it's harder to write it here in
normal text!
It's an ugly thing, of course, which is why there's no point in having such
a "formula". It's better simply to use first principles.

Mark
UWCAd, Trieste, Italy.

At 11:44 30/12/2004 -0500, Anthony Lapinski wrote:
> Neglecting air resistance, we all know that the maximum range for a
> projectile occurs when the launch angle is 45° on level ground. But what
> if the object is launched from a cliff of height H above the ground? Here,
> the maximum range occurs at less than 45°. I've searched most of the
> college texts I have, but I can't find a "range formula" that has the
> height included. Is there such an equation with an initial height (similar
> to R = v^2 sin2q/g on level ground)?