From: anthony_lapinski at PDS.ORG (Anthony Lapinski)
Date: Thu Dec 30 11:45:31 2004
Neglecting air resistance, we all know that the maximum range for a
projectile occurs when the launch angle is 45° on level ground. But what
if the object is launched from a cliff of height H above the ground? Here,
the maximum range occurs at less than 45°. I've searched most of the
college texts I have, but I can't find a "range formula" that has the
height included. Is there such an equation with an initial height (similar
to R = v^2 sin2q/g on level ground)?