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Re: [Phys-l] Absolute four-momentum of massless particles



On 09/30/2010 08:30 AM, Derek McKenzie wrote:

2. It can be helpful to think of the four velocity vector as a
'proper time vector' so that we can see intuitively what goes wrong
in the massless case (loosely - time stands still). I'm tempted to
say the proper time vector of a photon is the zero vector,

Be careful there. 4-velocity is related to proper time,
but it's not the same thing. Indeed it is _inversely_
related. U goes like d/dτ, with τ in the denominator.

Let's see how that works, focusing on U rather than τ.
We consider the case of a particle with a very small but
nonzero mass. I wish to _contrast_ the infinitesimal-mass
particle with the zero-mass particle -- not equate them!

Suppose a highly relativistic particle whizzes past the
laboratory. We know the mass is very small but we don't
know how small. We can measure the 4-momentum and we
find it is very close to P = [1, 1], well within the
uncertainty of measurement. If we are sure the mass is
nonzero we can write U = P/m = [1/m, 1/m] approximately,
subject to the constraint that U•U remains equal to -1,
which is no problem if we write U = [cosh ρ, sinh ρ] and
consider very large values of the rapidity ρ. We see
that the components of U are approaching infinity, not
approaching zero.

For the small-mass particle, there will always be SOME
frame in which it is at rest. For the zero-mass particle,
not so. The limit as m goes to zero is a singular limit,
so intuition can be expected to fail, and you have to be
very careful about the limiting cases.

Saying a function has a singular limit means that the
value of f(0) is not equal to the limit of f(x) as x goes
to zero. For more on this, including the unforgettable
"worm in the apple" example, I highly recommend the
article by Berry (yes, THAT Berry) at
http://www.phy.bris.ac.uk/people/berry_mv/the_papers/Berry341.pdf