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Re: [Phys-l] definitions ... purely operational, or not



At 13:28 -0700 11/09/2010, William Robertson wrote:

By the way, the folks at NASA and astronauts
increasingly use the term "microgravity" in an effort to clear this up.

And that, IMO is the worst offense of all. That will surely convince the students that there is no gravity in space. Using that term clears nothing up, it only introduces new prejudices. Yes we can say that in free-fall the astronauts are in a gravity-free environment, in accord with general relativity, but that is a very subtle concept, and not one we should subject students to until after they have had some time to get the intuitive ideas straightened out.

Every student, and many teachers, especially new ones, bring a lot of improper baggage with them when they study physics, and it is important that we lead them gently but firmly to the ideas about the world that we know work and which will serve them well in the world they will end up living in. IMO teaching them that mg is weight is not one of them, in spite of the fact that many come to us thinking that way. I like to start off with g expressed in terms of newtons per kilogram, to de-emphasize the connection of g to acceleration. Once they understand g as the gravitational analog to E, and that it uses analogous units, then they are beginning to understand just what all those forces that they have been fooling around with are, and they might even be open to the idea that mass could just as easily have been called "gravitational charge," and that it can also be thought of in terms of inertia. Or more likely we would use the converse idea, that what we call charge can be looked up as "electrical mass." Now we can talk about inertial mass, and write the gravitational version of NSL as m(inertial)*a = m(gravitational*g, and the electrical analog as m(inertial)*a = m(electric)*E. This enables us to show the students what I think is one of the greatmysteries of the world--that while the ratio of m(electric) to m(inerital) is a value that we can freely choose, the ratio of m(gravitational) to m(inertial) is always exactly 1. And we have no idea why that is true. (More properly, I have no idea why that is true, but there may be some esoteric explanations to be found in areas like string theory or the like that I have not been exposed to.)

Whether we want to go into all that is open to discussion, but I would argue most strongly that the word "microgravity," especially as used by NASA, should be banned from the English (and every other) language. I cringe every time I hear someone who damned well should know better say it.

Hugh
--

Hugh Haskell
mailto:hugh@ieer.org
mailto:haskellh@verizon.net

It isn't easy being green.

--Kermit Lagrenouille