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/snip/
I have not assumed that the E field is tangential to the loop. I am only assuming that because no boundaries are stated that no matter where I put the loop the integral (EMF) must be the same because nothing distinguishes one postion of the loop from another./snip/
If a boundary is specified then the symmetry is broken and I agree with you and JD that the field at any point can be easily argued to be unique and can probably be found by some clever argument.
Bob at PC
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From: Philip Keller [PKeller@holmdelschools.org
/snip/ suppose you cannot assume that the field has the same magnitude at all points on the loop -- say because it is that second loop you and I were both thinking of, near but not touching the first. At the point where the second loop is nearest the first, the electric field is pointing "the wrong way" - not in the direction of the current. /snip/the problem shows up regularly on the EM section of the AP physics C test but I don't recall symmetry or boundary conditions ever being mentioned.