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I do not know where the 0.14 mm comes from. In the first
description of your geometrical method (2/19/02) charges
+Q and -Q were located at the focal points.
In the yesterday's
message they are shifted by 0.14 mm toward the center of
symmetry.
In practical terms this is not significant;
I can not
locate equipotential points with an accurate less than 1 mm or
so.
But I still want to know. Numerical illustrations are very
useful; they help to make sure messages are well understood.
Following your first description I proceeded as follows.
After measuring DOP=50 V at the point (14,10) I calculated
K=7/3 =2.333.
This gives me the radius of the equipotential
circle = 5.250 cm.
Where is the center of this circle? It is at
x=19+1.837=21.837 cm (and y=10).
There were no 0.14 mm
shifting toward the center in this approach. What did I miss?
Ludwik Kowalski