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I am puzzled by the following problem
G Barnes (Am Journal of Physics, 1958,vol26, p7) defines coefficient of
restitution as follows:
e=3D (ae1 +be2)/(a+b)
e1 and e2 are Young coefficient of colliding bodies 1 and 2.
a and b are realtive hardness of substances 1 and 2.
How establish and explain the dependance of the coefficient of restitution
upon the hardness of bodies?
What is the link between hardness and rebound?
All comments are highly welcomed.
D. Ismael Youssouf.
This is a puzzlement! A rubber ball might have a good coefficient of
restitution (rebound) and fail miserably on a hardness test; whereas a
hard steel ball might do well on both (?). Must find somebody who knows
about these things. Any help out there? I'm curious.
-Bob
Bob Sciamanda