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Re: [Phys-L] When mathemeticians order pizzas

To find which pizza deal has the most toppings area, compare the ratio of the areas of pizza toppings by simply looking at the ratio of the squared diameters, corrected for the bare crust width, and multiplied by the number of pizzas of that size. Thus for two 10-inch pizzas with a 1-inch crust compared to a 14-inch pizza with a 1-inch crust:

The toppings area ratio = (8" x 8") x 2 / (12" x 12") = (2 x 4) / (3 x 3) = 8 / 9

If the 10-inch pizzas have only ½-inch wide crusts, then

The toppings area ratio = (9" x 9") x 2 / (12" x 12") = (3 x 6) / (4 x 4) = 9 / 8

Rick Strickert

-----Original Message-----
From: Phys-l <phys-l-bounces@mail.phys-l.org> On Behalf Of Scott Orshan via Phys-l
Sent: Friday, February 10, 2023 3:09 PM
To: phys-l@mail.phys-l.org
Cc: Scott Orshan <sdorshan@aol.com>
Subject: Re: [Phys-L] When mathemeticians order pizzas

[EXTERNAL EMAIL]

That's only if you consider the entire area. If you consider the NCSA, the non-crust surface area, you get less from the two 10" pies. The value of the pizza is in the toppings, and there's a higher outer-crust to topping ratio in the two smaller pies.

If you like the crust, like me, maybe that's a good thing, but I certainly don't want to pay as much for it.

Assuming a 1 inch outer crust, you are now comparing a 12" circle to two 8" circles. In this case, have them throw in some garlic knots or a soda. Be prepared to explain why to the high school kid behind the counter.

Message: 2
Date: Fri, 10 Feb 2023 10:46:26 -0500
From: Anthony Lapinski <alapinski@pds.org>
To: Phys-L@phys-l.org
Cc: "Watkins, Ann E" <ann.watkins@csun.edu>, Linda Benet
<benet@sbcc.edu>, Sam Smith <ssmith@igc.org>
Subject: Re: [Phys-L] When mathemeticians order pizzas
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I remember my high school math teacher saying that two 10" pizzas is
nearly equivalent to one 14" pizza. Just calculating the areas.

So 2 x (pi 5^2) = 50 pi

And the another is pi 7^2 = 49 pi

I've never forgotten this neat fact, but I've had no use for it either.



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