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On 2022/Apr/18, at 13:11, Brian Whatcott <betwys1@sbcglobal.net> wrote:
We might suppose that the large inductor is close-wrapped, so that the interwinding capacitance largely cancels the inductive reactance at say 1 kHz leaving 60 ohms contribution in a series circuit of 60 ohms, 188 ohms due to the capacitor at 1 kHz, and 100 ohms, a total of 348 ohms so that the coil contributes 60/348 of 5 volts = 0.9 volts of the volts drop.