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Re: [Phys-L] Inverse Square for reflected light



Another dumb question:

What are they using as the abscissa?

Assuming the original source is a point source, then
the relevant distance is
-- from the source to the mirror
*plus*
-- from the mirror to the detector.

To say the same thing the other way, if they imagine
the front face of the mirror to be a point source,
they've got the wrong abscissa. By a lot.

This would explain the result. As the jocular saying goes:
"To first order, everything is linear."

(That's not strictly true, but it's kinda mostly usually
true.)

In particular, if you have a square law (y=x²) and you
throw away most of x and look only at Δx, then y is (to
first order) a linear function of Δx.