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Re: [Phys-L] Bernoulli's equation

We just take conservation of energy (figured out prior to Bernoulli in my class) and divide everything my Volume.

I do this:
Ek + Eg + W = Ek + Eg + W (I know it is strange to put W on both sides, but we talk about how this is like the W done on either end, not total W).
0.5mv^2 + mgh + Fd = 0.5mv^2 + mgh + Fd
Divide everything by V
0.5(m/V)v^2 + (m/V)gh + F(d/V) =...
0.5(rho)v^2 + (rho)gh + F/A = ....

If we talk about W on each side as being any work done by external agents on that side. Sloppy text, but hopefully this makes some sense. Gottta run...

Paul Lulai
Physics Teacher
St Anthony Village S.H.
3303 33rd Ave NE
St Anthony Village, MN 55418

612-706-1146 ;

-----Original Message-----
From: Phys-l [] On Behalf Of R. W. Tarara
Sent: Friday, January 25, 2013 10:53 AM
Subject: Re: [Phys-L] Bernoulli's equation

Not so tedious--

Consider the total external energy by taking the work done on the fluid (Fs), the KE (1/2mv^2), and the gravitational PE (mgH) and divide the sum of these by volume. The assumption is some small volume near the boundaries of the fluid. Fs/V = Fs/As = P while the masses become mass volume densities.


Richard W. Tarara
Professor of Physics
Saint Mary's College
Notre Dame, Indiana

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From: "Anthony Lapinski" <>
Sent: Friday, January 25, 2013 11:36 AM
To: <>
Subject: [Phys-L] Bernoulli's equation

Teaching fluids now. Is there an "easy/conceptual" way to teach/derive
Bernoulli's equation?

P + 0.5pv2 = pgh = constant

Using conservation of energy and other formulas, this is the most
tedious/complicated derivation. I'm just looking for a different approach.

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