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Re: [Phys-l] momentum and energy



I thought that we were discussing the case of M/m >> 1.

ie a momentum transfer very close to 2mv.

[ Your expression is MV = 2mv / ( 1 + m/M ) ]
----- Original Message -----
From: Bob Sciamanda<mailto:trebor@winbeam.com>
To: Forum for Physics Educators<mailto:phys-l@carnot.physics.buffalo.edu>
Sent: Thursday, November 16, 2006 9:56 AM
Subject: Re: [Phys-l] momentum and energy


Al Bachmanwrote:
" > bc forgot that it is the momentum transfer that is constant, not V .
."

Not so.

The momentum transferred from m (initial velocity v) to M (initially at
rest) is:

MV = (2mMv) / (m+M) , which is NOT constant as M/m is varied.

What ARE held constant are the total system momentum and KE.

Bob Sciamanda
Physics, Edinboro Univ of PA (Em)