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[Phys-L] Re: centripetal force question



Anthony.

It seems as if you have finally got it right! Congratulations.

What took you so long??? : - )

Herb


On Tue, 15 Nov 2005 08:23:21 -0500 Anthony Lapinski
<anthony_lapinski@PDS.ORG> writes:

I've been thinking about this more after reading some of the
insightful responses. So then the rider pushes down (slanted) on the
seat/cycle. This adds a slanted downward force component to the cycle.
So for the
cycle, this y-component is downward (making N larger), and the
x-component
goes opposite to the frictional force, making the net horizontal force

smaller.
Right?


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