An amplification:
In a two particle Newtonian interaction, F(a on b) *dt = - F(b on a) *dt
leads directly to dp(b) = -dp(a) => conservation of p.
But one CANNOT write F(a on b) * dx(b) = - F(b on a) dx(a) because it is not
assured that dx(b) = dx(a), so that there is no assured equal exchange of
work or kinetic energy. The interaction forces operate over a common
temporal interval, but not necessarily over a common spatial interval.
Bob Sciamanda
Physics, Edinboro Univ of PA (Em) http://www.winbeam.com/~trebor/
trebor@winbeam.com
----- Original Message -----
From: "Bob Sciamanda" <trebor@WINBEAM.COM>
To: <PHYS-L@LISTS.NAU.EDU>
Sent: Thursday, February 17, 2005 3:00 PM
Subject: Re: collision question
| Because of the third law, all Newtonian interactions will conserve
momentum
| among the interacting objects. However, momentum can leave the system of
| interacting objects via E/M waves (dissipation of momentum?). Of course,
| overall momentum is still conserved. (Newton's third law is a special
case
| corollary of the conservation of linear momentum.)
|
| Bob Sciamanda