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*From*: Jim Green <JMGreen@SISNA.COM>*Date*: Wed, 4 Aug 2004 12:35:12 -0600

At 09:48 04 08 2004 , the following was received:

The point is that dS is an exact differential, but TdS is not:

Given any pair of well defined (initial and final) system states, the

integral of dS over any path (and with any valid constraints) connecting

those states results in the same numerical value. Not so for the integral

of TdS - its integral will be path (and constraint) dependent.

Bob, can you amplify this a bit? Maybe give an example?

Jim

Jim Green

mailto:JMGreen@sisna.com

http://users.sisna.com/jmgreen

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