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correction: There's work, and then there's work



Alas I wrote:

> -- the total energy drawn from the source is VQ.
> -- during charging VQ/2 is dissipated and the
> other VQ/2 ends up in the capacitor.
> -- during discharging another VQ/2 is dissipated
> and the capacitor ends up where it started.
> -- during the whole charge/discharge cycle a
> full VQ/2 is dissipated.

The last line should say a full VQ is dissipated
during the whole charge/discharge cycle, not VQ/2.
Sorry.