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That's what I'm referring to. These positive atoms experience a force
just as the free electrons experience a force. But due to their much
larger mass, their speed is much less, so they would be almost
undetected by measuring the current. Therefore, their energy would be
almost unaccounted for, using the (current) method you described. But
their energy is, actually, _exactly_ the same as the energy of the free
electrons. Therefore, in my opinion, using the current in the
determination of the energy is invalid, since it almost entirely
discounts the energy of the positive atoms.