Re: There's work, and then there's work

[David Rutherford <drutherford@SOFTCOM.NET>]

Bob LaMontagne wrote:
> David Rutherford wrote:
>
> > Why don't you assume that an equal amount of opposite charge flows in
> > the opposite direction. That would double the total charge and make the
> > energy equal to CV^2, not 1/2 CV^2. If the answer is no, please explain
> > why not (Obviously, I'm rethinking my claim that my theory gives 1/2
> > CV^2 and that 1/2 CV^2 is the correct answer).
>
> A galvanometer would respond to both negative charges flowing in one direction and
> positive in the other with the same direction of swing of the indicator. This is because
> the currents set up a magnetic field in the galvanometer coil which then interacts with a
> permanent magnet attached to a spring. The flow of negative and positive charges in
> opposite directions would set up the same magnetic field direction in the coil. Therefore,
> all possible currents are actually being measured. I can sense the bi-vector people
> wincing as they read this :-)
>
> Also, since the negative electrons are the only feasible current carriers available to
> actually travel through the wires, it's a rather mute point.

Then what happens to the positive charges on the other plate? Aren't
they affected by the potential difference between the plates? If not,
why not?

--
Dave Rutherford
"New Transformation Equations and the Electric Field Four-vector"
http://www.softcom.net/users/der555/newtransform.pdf

Applications:
"4/3 Problem Resolution"
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"Action-reaction Paradox Resolution"
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"Energy Density Correction"
http://www.softcom.net/users/der555/enerdens.pdf
"Proposed Quantum Mechanical Connection"
http://www.softcom.net/users/der555/quantum.pdf