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So we agree that |t2'-t1'| ~= |t2-t1|, for very, very small v.
Yes, approximately, but not exactly. The absolute deviation
from equality
gets greater as one looks at longer and longer time intervals.
Does |x2'-x1'| ~= |x2-x1|, for very, very small v?
No.
With the above stipulation that LA to San Diego distance is *not*
approximately zero.