Re: A Geometrical Proof of the Non-invariance of the Spacetime Interval

[David Rutherford <drutherford@SOFTCOM.NET>]

Michael Burns-Kaurin wrote:
> David Rutherford wrote:
>
> > In Special Relativity, the spatial coordinates assigned to an event are
> > fixed at the position of its occurrence in each frame, for all times.
> > The location of E1 is at x = 0 in F, for all times, and at x' = 0 in F',
> > for all times. Unfortunately, x = 0 and x' = 0 do not coincide for t > 0
> > and t' > 0.
>
> True, but not important.  Your original post deals with the spacetime
> interval between events.  The spacetime interval is specified by both
> position and time.  To find the spacetime interval, you must use both the
> position and time you specified for E1, that is, t=0 and x=0, and t'=0 and
> x'=0.

If, by spacetime interval, you mean the _magnitude_ of the separation in
spacetime between E1 and E2, I agree that it is invariant. But, as I
pointed out in previous posts in this thread, that is not what I'm
referring to. I pointed out that my terminology might be incorrect for
the reasons that I stated in one of those posts. If it's not the
magnitude of the spacetime interval between E1 and E2 that you are
referring to, please let me know.

--
Dave Rutherford
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