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This surface charge density result is just twice Smythe's result: pg 114;
Perhaps there is a discrepancy in what "Q" stands for; in Smythe it is the
total charge, added up over all disck surfaces.
David, I have been able to spend only sporadic moments on these things -
but I will "shortly" e-mail you some scanned pages of Smythe in TIFF
Physics, Edinboro Univ of PA (em)
----- Original Message -----
From: "David Bowman" <David_Bowman@GEORGETOWNCOLLEGE.EDU>
Sent: Sunday, February 11, 2001 01:44 PM
Subject: Re: capacitance of a disk
Regarding Ludwik's question:
. . .
Yes. In my most recent post I showed how to calculate the surface
charge density for this limiting flat disk case as well as for the
generic spheroid conductor case. To recap the result for the disk
the surface charge density is:
[sigma](r) = Q/(2*[pi]*R^2*sqrt(1 - (r/R)^2))
. . .