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Re: Toward the equilibrium



Referring to this:

>Suppose that at t=0 a charge of 1 microC is deposited at one
>point of a copper sphere whose diameter is one meter. I used
>to say that "the equilibrium is going to be established very
>quickly, perhaps in a couple of nanoseconds or so. Why?
>Because it can not be faster than 3.3 ns; the time light
>needs to cover the distance of 1 m in air.
>
>1) Do charges travel to final destinations through the entire
>volume or do they travel mostly near the surface?

Tim Folkerts wrote:

Neither! The +1 uC doesn't travel through the conductor at all! (But I'll
admit I never thought about it until you asked ....)

You need to start before t=0. As the +1 uC is brought close to the
conductor, the electrons in the copper are already rearranging themselves.
The point on the conductor nearest the external charge will have a -1 uC
charge, while the rest will have a +1 uC surface charge. When the external
charge finally reaches the conductor at t=0, it only needs to travel to the
-1 uC of electrons waiting at the nearest side.

No significant travel of electrons will be needed to establish equilibrium.
Other than a little "ringing", it seems that equilibrium is established AT
t=0. Come to think of it, perhaps the "ridiculous" answer that someone
quoted and I already deleted :-( of something like 10^-18 s actually is
correct.

I am not sure that this is correct. It is true that the sphere is strongly
polarized before it is touched and that the injected +Q mixes with the
-Q nearby. But the net charge +Q, at time zero, is on the other side of
the diameter. In other words, the distribution at t=0 is not uniform
over the sphere, as it becomes when the equilibrium is established.
How long does it take to equilibrate charges? Anything less than
1 ns would be unrealistic for the sphere of one meter.
Ludwik Kowalski