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compared to
"Perfectly well"? Equilibrium thermodynamics cannot describe the
states of a gas *during* a free expansion.
Good grief! Leigh was talking about "slow" processes ie slow
the relaxation time of the system -- A free expansion can hardly be"slow"
in this regard!!!Even if "they" in the statement "One might say they are described
Jim Green
Glenn, to your questiongive
Why does equilibrium thermodynamics work very well in one
situation and very poorly in another?
I would answer that equilibrium thermodynamics works well in both
cases you describe. In both cases it does what it claims to do;
a complete description of the initial and final equilibrium statesof
the systems.states
It won't tell you anything of any non-equilibrium intermediate
process. In an irreversible process, such as a free expansion, many
thermodynamic parameters of the system such as pressure and
temperature are undefined and indefinable. In an (artificial)
quasi-static process, all intermediate states would be equilibrium
states, so I guess thermodynamics will tell you all about those
but that wouldn't be much use, would it? Nevertheless suchartificial
processes are the strength of thermodynamics since they allow youto
tread a path through natural irreversible changes from a realstate.
equilibrium initial state to a real initial equilibrium final
Brian McInnes