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Robert Carlson wrote:
> [John Mallinckrodt] writes:
>
> > I see lots of potential here for confusion down the line. I happen to
> > like the identification of weight with the magnitude of m*a_freefall
> > because that *is* what a scale reads (i.e., they are using my
definition),
>
> Scales will read whatever you calibrate them to read.
I simply don't know what to make of this response in the context of our
discussion. It doesn't seem intended to promote clarity.
for
> > We know and that is certainly your right. We would have it be
otherwise
> > since there is already a perfectly good name for the force of gravity
> > (i.e., "the force of gravity") and a very meaningful alternate use
theshorter,
> > name "weight."
>
> I prefer weight, it is much shorter than "the force of gravity."
Robert. You can believe me when I say, I know that.
> > > Would those advocating not using weight also advocate not using
> > > acceleration, but instead always say the time rate of change in
> > > velocity?
> >
> > Why would we do that? I see no advantage to be gained.
>
> The advantage is that it is shorter and means the same thing. Why do
> mathematicians define m = (delta y)/(delta x)? I conclude it is
and
> easier to say slope, than delta y divided by delta x.
Let me get this straight. In response to your question (perhaps you would
like to read it again), I express puzzlement as to why you would suggest
such a thing. Your response leaves me even more puzzled and I can only
read it as saying that *you* think "it" (i.e., "time rate of change of
velocity") is a shorter phrase than "acceleration." I suspect that you
simply didn't read carefully.
> > Everyone that I
> > know agrees that acceleration IS the time rate of change of velocity.
> > I've never heard anyone suggest a good alternate use for the word
> > acceleration.
>
> Everyone would also agree that weight is the force of gravity if they
would
> read their physics texts.
Correct me if I am wrong, but I sense that you are saying you really
aren't interested in my *reasons* for promoting a different definition.
> It is not my definition. I do not presume to be on the level to make
> fundamental physics definitions. I will leave that to those with much
more
> knowledge than myself. Perhaps this is you John, convince me.
I have tried my best to explain rationally the reasons that I prefer a
different definition. You seem to want to have it that I am simply
"wrong." I see no point in beating my head against the wall.
John Mallinckrodt mailto:ajm@csupomona.edu
Cal Poly Pomona http://www.csupomona.edu/~ajm