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Re: Need soln explaination




I got a problem out of an older physics text (one without a solutions
manual). My students and spent a while debating the method of attaining
the solution. Can someone explain how they would solve it -using energy.

PROBLEM
Masses of 3 kg and 2 kg are hanging at opposite ends of a cord that
passes over a frictionless pulley. The system is held stationary for a
while, then released. What will be the speed of the masses when the 3 kg
mass has descended 0.5 m below its starting point? (USE ENERGY
RELATIONSHIPS TO SOLVE.)

-tony



Change in gravitational potential energy of the system

= -3gh+2gh = -gh (3 kg mass loses PE and 2 kg mass gains PE)

Change in KE = (1/2)3 v^2 + (1/2)2 v^2 = 5v^2/2

Conservation of energy gives

5v^2/2 - gh = 0

Solve this using h=0.5 m and you get v=1.4m/s.