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Re: Work/Energy theorem



Hi Herb,

You wrote:

Well, it's not quite that simple but almost. The work done by an internal
force is zero if the object is rigid; i.e., the relative position of the
particles in the object remain constant.

I don't think this is quite correct. For a rigid object the total work
done by each internal action/reaction force pair is zero but the work done
by each individual force is not necessary zero.


Gene

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Eugene P. Mosca 410-293-6659 Work
Physics Department 410-267-0144 Home
572 Holloway Road 610-683-3597 Summer
U.S.Naval Academy Mailstop 9C, Michelson Rm 339
Annapolis MD 21402 email: mosca@nadn.navy.mil
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