An obvious example =>
By definition, a geosynchronous satellite has a ZERO apparent velocity.
Just as obviously, this is achieved by matching the earth observer's ANGULAR
velocity, not his linear speed. The observer and satellite LINEAR speeds are
vastly different!
-----Original Message-----
From: Bob Sciamanda
Sent: Monday, March 03, 2014 11:23 AM
To: Bob Sciamanda ; Phys-L@Phys-L.org
Subject: Re: [Phys-L] Trick photography?
I'm still learning (a good sign)! ==>
I am just realizing that the apparent moon speed is NOT calculable as the
moon's linear orbital speed minus the linear spin speed of an earth surface
point.
IE., Vap is NOT= {(6.28*250000)/(30*24) - (6.28*4000)/24} miles/hr. This is
grossly wrong - even in direction!
Instead, Vap = {6.28/(30*24)-6.28/24}*250000 miles/hr. => the relative
ANGULAR velocity times the moon's orbital radius.
It is incorrect to treat the earth observer as viewing a linear motion from
a linear moving frame. We must acknowledge that the earth observer is
viewing a rotational motion from a rotational frame. Note that this turns
the moon's actual EASTWARD motion into the observed WESTWARD motion. The
linear mistreatment fails to even do this.
Again, thanks to John M for leading me to this realization.
Bob Sciamanda
Physics, Edinboro Univ of PA (Em)
treborsci@verizon.net http://sciamanda.com