[Phys-L] Re: relativistic doppler effect (was: The view from the Enterprise.)

[John Mallinckrodt <ajm@CSUPOMONA.EDU>]

Rick writes:

> Which pretty much brings me back to my initial question.  As an observer in
> a ship moving at 87% the speed of light towards a star (but viewing the star
> as moving towards me) and knowing special relativity, shouldn't I expect the
> period of atomic emitters to have increased by a factor of two, therefore
> the frequency to have decreased by a factor of two, but then the wavelengths
> contracted by a factor of 2---washing out and leaving only a classical
> Doppler shift?  I know this is too simplistic, but where is the mistake?

Let's take this specific example and just run some numbers.  Suppose
the rest frequency is 2 Hz so that, at v = (3/4)^1/2 c it becomes 1
Hz.  The source emits a pulse and one second later (according to the
observer "at rest") it emits another pulse.  In that one second the
source moves (3/4)^(1/2) of a light second while the first pulse
moves a full light second.  The pulses are, thus, 1 - (3/4)^(1/2) of
a light second apart.  This is the wavelength and it corresponds to
an observed frequency of

    f_obs = [1 - (3/4)^(1/2)]^-1 Hz = 7.46 Hz

in agreement with the general formula.

--
John "Slo" Mallinckrodt

Professor of Physics, Cal Poly Pomona
<http://www.csupomona.edu/~ajm>

and

Lead Guitarist, Out-Laws of Physics
<http://www.csupomona.edu/~hsleff/OoPs.html>
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