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Re: latent heat of evaporation



There is a temeprature dependence to L, namely,

dL/dT = C_pv - C_pw

(refer to Bohren: Atmospheric Thermodynamics, p197)

This is not related to bubbles, just the temperature dependence of the
enthalpies of the liquid and vapor.

Bob at PC

*********** REPLY SEPARATOR ***********

On 9/27/2004 at 8:58 AM Ludwik Kowalski wrote:

On Sunday, Sep 26, 2004, John Denker wrote:

Ludwik Kowalski wrote:
As far as i know no bubbles are formed when evaporation takes place
without boiling, for example at 90 C. Molecules
escape from a flat surface overcoming surface tension forces. That is
when, I suppose, the value of 540 cal/g is valid. This topic is new
to
me. I do not know what to expect when bubbles are formed. Should L
become larger or should it become smaller than 540? Perhaps someone
will supply the answer based on thermodynamics. Or on laboratory data.

How about an answer based on conservation of energy?

Suppose you evaporate 50g of water from a vessel at 100C,
and recondense it in another vessel at 98C.

What happens to the energy?
What does this tell you about the latent heat?

Are you saying, John, that to accept two different values of L (one for
evaporation without boiling and another with boiling) would
automatically lead to the violation of conservation of energy? I am not
convinced that this is true, unless additional restrictions are
imposed. The energy conservation makes the magnitude of the latent heat
of evaporation equal to the magnitude of the latent heat of
condensation, assuming, for example, that both take place without
forming bubbles. The same would be true for evaporation and
condensation involving bubbling (if condensation of that kind could be
imagined).