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Re: Orbital Kinetic Energy

E = v^2/2 - mu/r = h^2/(2rp) - mu/rp

rp = radius at periapsis
mu = GmM

rp=a(1-e) and h=sqrt(mu p) = sqrt(mu a(1-e^2))

By substitution, E = -mu/(2a)

I hope that helps,
Peter Schoch

Brian Blais wrote:


I was wondering if anyone knew of a calculation showing that the kinetic
energy of an object in a circular orbit is equal to half of the potential
energy, where the calculation does *not* use acceleration or force at all. Is
there an argument for this based purely on energy concepts? It occurred to me
that there should be, but I can't think of it.


Brian Blais