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*From*: Peter Schoch <pschoch@NAC.NET>*Date*: Mon, 2 Feb 2004 21:04:44 -0500

E = v^2/2 - mu/r = h^2/(2rp) - mu/rp

rp = radius at periapsis

mu = GmM

rp=a(1-e) and h=sqrt(mu p) = sqrt(mu a(1-e^2))

By substitution, E = -mu/(2a)

I hope that helps,

Peter Schoch

Brian Blais wrote:

Hello,

I was wondering if anyone knew of a calculation showing that the kinetic

energy of an object in a circular orbit is equal to half of the potential

energy, where the calculation does *not* use acceleration or force at all. Is

there an argument for this based purely on energy concepts? It occurred to me

that there should be, but I can't think of it.

thanks,

Brian Blais

-----------------

bblais@bryant.edu

web.bryant.edu/~bblais

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