Re: There's work, and then there's work

[David Rutherford <drutherford@SOFTCOM.NET>]

David Rutherford wrote:
> David Rutherford wrote:
> > I claim that the results of the calorimetry may be due to the energy of
> > the positive atoms, not the free electrons. So if you combine the
> > results of the "current experiment" that you described, which only gives
> > the energy of the free electrons, with the calorimetry experiment, you
> > get 1/2 CV^2 + 1/2 CV^2 = CV^2 for the total energy stored in the
> > capacitor.
> >
> > I'm not claiming that either one of the experiments, alone, will give
> > CV^2, but why couldn't you combine both experiments together in the same
> > experiment? That is, do the calorimetry experiment and the current
> > experiment at the same time, using the same circuit, and combine the
> > results of the two measurements.
>
> I was hoping to get an answer to this question. Is it valid to combine
> (add) the results of both experiments if they are done at the same time
> on the same circuit? If not, why not?

An analogy might be measuring the amount of water in an elevated tank by
measuring the water that flows through a hose attached to the tank after
the valve is opened. Imagine that the hose has a hole in the side of it,
so that the volume of water flowing out of the hole is exactly equal to
the volume flowing out the end of the hose. In analogy with the
capacitor experiment, the water flowing out through the side would
represent the energy lost to heat dissipation in the calorimeter
experiment, and the water flowing out the end would represent the
current in the current experiment.

When you do the current experiment, alone, energy is actually being
dissipated as heat into the environment, but this heat energy is not
being accounted for. Likewise for the calorimeter experiment, except
that it is the current that is not being accounted for. In my opinion,
using the water tank analogy, again, what is really being measured in
the individual experiments is the amount of water flowing through only
_one_ of the holes. In the case of the calorimeter experiment, you are
measuring only the water flowing out of the side of the hose and
claiming that is the amount of water stored in the tank. In the case of
the current experiment, you are measuring the amount of water flowing
out of the end of the hose and claiming that is the amount of water
stored in the tank. Since the two measurements agree, you claim that
each result corroborates the other. Unfortunately, each result alone
gives only _half_ of the actual amount of water in the tank. In order to
get the correct result, you have to combine the two individual results.

--
Dave Rutherford
"New Transformation Equations and the Electric Field Four-vector"
http://www.softcom.net/users/der555/newtransform.pdf

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