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Not quite. The derivative you took was with respect to *velocity* so
As I was watching a video with my class (for the unteenth
time) I made a startling observation/conclusion. As a look
at the KE = 1/2mv^2 equation and take the derivative I
believe I get mv which is momentum (p). Now clearly
there has to be a relationship between KE and p simply
because we are talking about the same mass and velocity.
As I understand derivatives, if I was graphing the delta
KE of an object with respect to time, the slope of said
graph would be the momentum of the object at that time.