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Re: Polarized light



Well, also not quite.

First: It's the difference between reflection from an insulator and a
conductor, as M. P. explains. In one case the interaction is with bound
electrons and the other by quasi-free electrons. This difference is
phenomenologically described by a complex index of refraction.

When plane polarized light (not exactly p or s) is reflected by a metal, it
becomes elliptically polarized, because the phase of the components changes
by other than zero or Pi for the s & p components (generally). Furthermore
as with an insulator, the the reflection coefficients differ. (excepting
at normal and grazing incidence).

Except for their confusion of the principle angle with the
pseudo-Brewster's angle, Jenknis and White have a good discussion on
metallic reflection.

I'm surprised there is confusion on this matter, as I assume nearly all
optiks texts discuss this, some including derivation of Fresnel's relations
for absorbing media.

bc




Herbert H Gottlieb wrote:

In response to Scott Krefetz question (below) about
the lack of polarized light reflections from polished metal,
Mark Phillips, C.M.Phillips@Metrologic.com replies:

Well, the statement is not EXACTLY true, there is ALWAYS some
degree of polarization at a reflective interface.
However, the difference between a transparent material
(such as glass) and a reflective material (metal) is that the
component of the polarized light which aligns best with the
material is TRANSMITTED through the glass, leaving the
remaining polarization component to be reflected. In a metal,
with a very high refractive index, it is thought that the
electron cloud on the surface of the metal responds
equally well to either polarization component.

Mark Phillips

"Mr. Krefetz" <science98@HOTMAIL.COM> asks

An interesting observation of polarized light. It is polarized when
reflected off of a transparent material (glass or plastic) which
follows the explanations from the textbook. But when the
reflection is from a polished metal surface, the light is not polarized.

Why?

Thanks
Scott Krefetz
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