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In the arrangement shown in the figure, a potential difference V
is applied, and C1 is adjusted so that the voltmeter between
points b and d reads zero. This "balance" occurs when C1 = 4.00
microF. If C3 = 9.00 microF and C4 = 12.0 microF, calculate the
value of C2.
______________________
| | |
| V ===C1 ___ ===C4
----- b|____/ V \___|d
--- | \___/ |
| ===C2 ===C3
|_________|____________|
______________________
| | |
| V ===4 ___ ===12
----- b|____/ V \___|d
--- | \___/ |
| ===3 ===9
|_________|____________|
I learned something tonight, something that I previously "knew"
but apparently did not "understand." The lesson was delivered
after scratching my head for way too long over the [...]
seemingly straightforward problem (which I had made the mistake of
assigning before solving) from the current edition of a well known
intro text. I thought others might enjoy the challenge as well.
Here's the problem (what's the lesson?)
______________________
| | |
| | $
| === Std $ constant
| | $ inductance
_|_ | ___ |
/exc\ b|____/det\___|d
\___/ | \___/ |
| | |
| | $ adjustable
| === Unknown $ inductance
| | $ on same core
|_________|____________|