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Re: [Phys-L] This Week's "Charming" CarTalk Puzzler

This puzzle has been a part of Hewitt’s Next-Time questions for sometime.
A nice graphic and his answer:
http://www.physicslab.org/Document.aspx?doctype=5&filename=Compilations_NextTime_VergeSinking.xml <http://www.physicslab.org/Document.aspx?doctype=5&filename=Compilations_NextTime_VergeSinking.xml>


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Scott Goelzer
Physics, Engineering, & Chemistry
Coe-Brown Northwood Academy
Northwood NH
sgoelzer@coebrown.org
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On Oct 13, 2022, at 10:38 AM, Brian Whatcott <betwys1@sbcglobal.net> wrote:

This puzzle seems to depend on the greater stiffness of water, compared with air, I'd say.
On Thursday, October 13, 2022 at 09:31:39 AM CDT, Carl Mungan via Phys-l <phys-l@mail.phys-l.org> wrote:

Should we assume the weight doesn't initially touch the bottom of the pool,
nor does it touch the bottom while the balloon is being pushed down?

On Thu, Oct 13, 2022 at 8:23 AM David Bowman <
David_Bowman@georgetowncollege.edu> wrote:

This week's CarTalk Puzzler has a physics theme that may be appropriate
for 1st year physics students. Those teaching them may want to give this
out as an extra credit or in-class discussion type of problem.

Below is a verbatim quote of it from the CarTalk Puzzler email from their
website.
_____________________________________________
<Charming Balloon

Now it's time for our charming new puzzler. For lack of a better word, I
guess I can call it charming, but you all be the judge.

Here it is.

You have a balloon that is filled with air. Like a balloon, you'd get at
the circus. You tie the knot with a string at the end, and you also tie a
weight to the string. The purpose of the weight is because you're going to
place the balloon in water, like a swimming pool, such that the weight will
keep the balloon's top just even with the top of the water as we describe
in geometry, tangential to the surface.

The entire balloon is submerged in the water, except for the very top. All
right, and the weight is keeping the balloon from rising beyond the surface
of the water. We can all imagine this would work right? Balloons want to
float. If the weight were not there, or if you came by with your scissors
and snipped the string, it would pop right up.

For the sake of this puzzler, you don't have to know what the amount of
the weight is. The weight of weight could be anything. It doesn't matter,
for the sake of this puzzler.

Okay now, you take your hand and push down on the balloon. You push it
down all the way into the water, one foot down. So, when you push the
balloon down one foot and of course, it will go down nice and smoothly as
you push it down.

And then, when you take your hand away, what happens?

What happens and why?>
_____________________________________________

David Bowman

_______________________________________________
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l



--
Carl E. Mungan, Professor of Physics 410-293-6680 (O) -3729 (F)
Naval Academy Stop 9c, 572C Holloway Rd, Annapolis MD 21402-1363
mailto:mungan@usna.edu http://usna.edu/Users/physics/mungan/
_______________________________________________
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l

_______________________________________________
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l