|Chronology||Current Month||Current Thread||Current Date|
|[Year List] [Month List (current year)]||[Date Index] [Thread Index]||[Thread Prev] [Thread Next]||[Date Prev] [Date Next]|
From: Phys-l <firstname.lastname@example.org<mailto:email@example.com> > On Behalf Of Dan Beeker via
Sent: Tuesday, June 1, 2021 9:20 PM
To: firstname.lastname@example.org <mailto:email@example.com>
Cc: Dan Beeker <firstname.lastname@example.org <mailto:email@example.com> >
Subject: Re: [Phys-L] Phys-l Digest, Vol 198, Issue 1
I should have been more explicit.
1. You are correct. S is the cross sectional area. In terms of radius
(a) the formula would be
a = b(x^-epsilon) = b/(x^epsilon)
The factor of 2 in th formula for S comes because the area is (pi)r^2.
Sub a into the area formula.
area S = (pi)r^2 = (pi)a^2 = pi[b/x^epsilon]^2 = pi[b^2/x^2epsilon]
pi*B^2 morphs into the constant b.
2. As far as whether the exponent epsilon is positive or negative, I'llhave to
ponder this. I think epsilon should be positive so the function getssmaller as one
moves away from the large end of the bell.
3. And I see a typo in
If epsilon = 0 you have a cylindrical horn. If x = 1 you have a conicalhorn.
If epsilon = 0 you have a cylindrical horn. If epsilon = 1 you have aconical horn.
4. And I believe I made another typo which may explain the confusion.
where a is the bore radius of the horn and x0 is the small end of thehorn.
where a is the bore radius of the horn and x0 is the large end of thehorn.