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Consider the equation
dE = T dS - P dV [1a]
that equation is only valid for a path complete developed through
equilibrium states and in a reversible process
Why do you say that? This equation is basically a Taylor expansion of a
function. As John Denker has already said, it’s just calculus.
Reversibility does not enter into it *unless* you try to equate TdS with
“heat” and -PdV with “work” which is a different ball of wax altogether.
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Carl E Mungan, Assoc Prof of Physics 410-293-6680 (O) -3729 (F)
Naval Academy Stop 9b, 572C Holloway Rd, Annapolis MD 21402-1363
mailto:mungan@usna.edu http://usna.edu/Users/physics/mungan/
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