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*From*: Paul Lulai <plulai@stanthony.k12.mn.us>*Date*: Mon, 21 Jul 2014 19:07:51 +0000

Bob,

Thanks for your persistance.

I was missing a basic point, while |r| increases, the angle changes & the cross product does not change. I see it now.

I appreciate your help, along with that of the others.

Have a good one.

Paul.

.:. Sent from a touchscreen .:.

Paul Lulai

-------- Original message --------

From: Bob Sciamanda

Date:07/21/2014 2:02 PM (GMT-06:00)

To: Phys-L@Phys-L.org

Subject: Re: [Phys-L] angular momentum

OK, let's use your data ==>

r=5i + 10tj, here I and j are unit x,y vectors.

v=0i +10j ==>

perform the cross product r x v ==>

Here is the z component of the cross product ==> (AxB)_z = k(Ax*By -

Ay*Bx), where k is a unit z vector

r x v = k(5*10 - 0*0) = 50k, a constant

Keep asking, if it's not clear.

Bob Sciamanda

Physics, Edinboro Univ of PA (Em)

treborsci@verizon.net

www.sciamanda.com<http://www.sciamanda.com>

-----Original Message-----

From: Paul Lulai

Sent: Monday, July 21, 2014 2:38 PM

To: Phys-L@Phys-L.org

Subject: Re: [Phys-L] angular momentum

I am used to seeing and using...

L=r ×p = r × mv.

What happens when the object has:

v_y_ = +10

v_x_ = 0

And the original position of the object is (5,5) relative to my origin.

Then even though p is constant, the position vector r is constantly changing

in both magnitude and direction. In this case, L is not constant.

No torques, no interactions with something outside of my system (the ball

and my oddly chosen origin), and L is not conserved.

Why is that?

There seems to be some sort of a condition for the origin. I am not used to

that.

Thanks again for the time help.

Paul.

.:. Sent from a touchscreen .:.

Paul Lulai

-------- Original message --------

From: treborsci@verizon.net

Date:07/21/2014 1:05 PM (GMT-06:00)

To: Phys-L@Phys-L.org

Subject: Re: [Phys-L] angular momentum

Consider the motion of a ball, free of all forces, to be the constant

velocity path: x=a (a constant), and y= vt (v is its constant speed).

Its angular momentum about the origin (0,0) is simply m*a*v, a constant in

time. In the same way, Its angular momentum about any fixed point is a

constant in time .

Bob Sciamanda

Physics, Edinboro Univ of PA (Em)

treborsci@verizon.net

www.sciamanda.com<http://www.sciamanda.com>

-----Original Message-----

From: Paul Lulai

Sent: Monday, July 21, 2014 1:36 PM

To: Phys-L@Phys-L.org

Subject: [Phys-L] angular momentum

Hello.

I am finding I have some questions about conservation of angular momentum

that I hadn't considered in the past. If I am investigating the angular

momentum of a soccer ball about a point, is angular momentum only conserved

if the ball is orbiting about the center of a circular path or a foci of an

ellipse? Certainly a ball traveling directly west across a field does not

have its angular momentum conserved.

I am completely excluding the idea of impulse, torques, and isolated systems

at this point. I just found I haven't thought about this aspect before.

Thanks for your thoughts.

Paul.

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**References**:**Re: [Phys-L] angular momentum***From:*Paul Lulai <plulai@stanthony.k12.mn.us>

**Re: [Phys-L] angular momentum***From:*"Bob Sciamanda" <treborsci@verizon.net>

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