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Re: [Phys-L] Electrolysis under Pressure

Now, during the electrolysis, applying exactly 1.229 V at 298 K will
take the system to deltaG° = 0 kJ
This corresponds to an equilibrium system with K = 1: pure water and
1 bar of each gas. Applying double the voltage will drive the reaction
to beyond equilibrium state again.

is posible to do that in practice?

Diego Saravia