When the bal is released just below the surface there is only the buoyant
force (and gravitational force) acting on it.
When the ball is released far below the surface consider it when it is just
below the surface. There is now an additional force acting on it (a
velocity dependant resistance of the water). Hence just below the surface it has
less upwards acceleration.
Of course it now has an initial upwards velocity. I expect different
liquids will have different details. density, viscosity, turbulence will all
play a part.
Alex. F. Burr
In a message dated 7/1/2013 9:30:24 P.M. Mountain Daylight Time,
zubarsky@gmail.com writes:
When I pushed the ball deeper, about 2 or 3 feet below the
surface and let go, the ball would rise and then sort of sputter at the
surface and not rise above the surface at all. Does anyone know how to
explain this.
Mike Barr
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