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Re: [Phys-L] playing for keeps

Bruce,

You left out the area of the bounding cube/area of sphere which also equals 6/pi. Bet we can find a "reason" for those two apparent coincidences!

John Mallinckrodt
Cal Poly Pomona

On Jun 29, 2013, at 4:57 PM, Bruce Sherwood wrote:

Here's an oddity:

bounding square/circle:
perimeter 8r/2pi*r = 4/pi = 1.27
area 4r^2/pi*r^2 = 4/pi = 1.27 (odd that the ratios are the same)

But for volume, bounding cube/sphere
8r^3/(4/3)pi*r^3 = 6/pi = 1.91

Bruce
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