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-----Original Message-----
From: Phys-l [mailto:phys-l-bounces@phys-l.org] On Behalf Of Bruce Sherwood
Sent: Thursday, February 28, 2013 11:51 AM
To: Phys-L@phys-l.org
Subject: Re: [Phys-L] amusing electrostatics exercise
Ampere's law for axial symmetry lets you get the magnetic field inside a
wire as well as outside, so you could if you wish calculate the field at
all locations.
Bruce
On Thu, Feb 28, 2013 at 8:26 AM, Jeffrey Schnick
<JSchnick@anselm.edu>wrote:
In the two skinny wire model, find the magnetic field due to each wirecoordinate system. Add the results.
as if it were the only wire. For one wire of infinite length there is
enough symmetry to get the magnitude and direction of the magnetic
field at all points in space not on the skinny wire. Do the
coordinate transformation needed to get both results in the same
The result is only appropriate for points in space outside the_______________________________________________
surface of the original wire.
-----Original Message-----use
From: Phys-l [mailto:phys-l-bounces@phys-l.org] On Behalf Of John
Denker
Sent: Thursday, February 28, 2013 12:25 AM
To: Phys-L@Phys-L.org
Subject: Re: [Phys-L] amusing electrostatics exercise
On 02/27/2013 02:45 PM, Bruce Sherwood wrote:
At the same
location as before, use Ampere's law to calculate the vector
magnetic field at that location.
How do you do that?
The only Ampère's law of which I am aware allows us to calculate the
/average/ field, averaged over some specified loop. I do not see
how to
it to calculate the "vector magnetic field" at any "location" ...especially given
that the problem expressly said that the hole was "non co-axial".rules
That
out the the sort of symmetry that might allow us to infer a localfrom
value
the average value. The problem did not suggest any other symmetry,the
so
only reasonable interpretation I can imagine is that the situationover
is not symmetrical.
Also, the problem explicitly asked for "the mag. field" not some
average
the field. I say again, there cannot possibly be any simple solution.hole
Counterexamples abound. A hole on the left side is not equivalent
to a
on the right side. The current knows the difference. The fieldthe
knows
difference._______________________________________________
_______________________________________________
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