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-----Original Message-----_______________________________________________
From: Phys-l [mailto:phys-l-bounces@phys-l.org] On Behalf Of Bob
Sciamanda
Sent: Friday, November 22, 2013 2:26 PM
To: Phys-L@Phys-L.org
Subject: Re: [Phys-L] standard dc circuits
It might help to realize that the fields are produced by charges which
accumulate on wire surfaces AND wherever there is a change in
conductivity, eg at resistor terminals.
Bob Sciamanda
Physics, Edinboro Univ of PA (Em)
treborsci@verizon.net
http://mysite.verizon.net/res12merh/
-----Original Message-----
From: Paul Lulai
Sent: Friday, November 22, 2013 2:11 PM
To: Phys-L@Phys-L.org
Subject: [Phys-L] standard dc circuits
I have a question about the junction rule for simple dc circuits.
I have a battery connected to 1 lamp, then split to 2 lamps in
parallel and back to the battery.
For easy numbers, if 1 amp flows through the first lamp, then 0.5 amps
flow through each lamp in parallel (if all lamps are ideal).
Using the junction rule, I know that current into each junction or
node must equal the current out of each junction or node. It is
simply a conservation of charge in that area.
How does that reconcile with a fields approach? I might have some
incorrect notions below. I am open to correction.
The batteries produce a field that move charges already present in the
wire.
If all wires are of the same material, diameter, length (and so on)
why is the current less in the parallel branches than in the wires
before and after the parallel branch? Does something make the field
in the parallel branches smaller than the field in the series portion
before and after the parallel branch? I don't see it.
Thanks for any input.
Paul.
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_______________________________________________
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