Re: [Phys-l] Thermodynamics question

[John Denker <jsd@av8n.com>]

On 01/10/2010 03:46 PM, LaMontagne, Bob wrote:
> Yes, my dw, by definition,  includes all energy tranfers out of the
> system that are not related to temperature differences.

Does that answer the question(s) of interest?

If not, please re-ask the question(s).

> As I stated in the beginning , disavowing du = dq - dw is not going to help me here.

Agreed.

I still think it would be a good idea for other reasons, but
I won't hijack this thread with that discussion.  See next
message.