In a message dated 1/1/2010 6:16:03 PM Eastern Standard Time,
RLAMONT@providence.edu writes:
I'm having a hard time with the dimensions of the equation below.
Bob at PC
________________________________________
From: phys-l-bounces@carnot.physics.buffalo.edu
[phys-l-bounces@carnot.physics.buffalo.edu] On Behalf Of Spinozalens@aol.com [Spinozalens@aol.com]
Sent: Friday, January 01, 2010 3:44 AM
To: phys-l@carnot.physics.buffalo.edu
Subject: [Phys-l] Bekenstein Bound and the Davies-Hawking-Unruh effect
From the second law of thermodynamics we have
dE/dS=k*T
Normally it looks like this.
dS=dQ/T I am using k*T because the Hawking Black Hole equation is defined
in MKS or CGS units.