Re: [Phys-l] Capacitance problem

["Bob Sciamanda" <trebor@winbeam.com>]

Boo-boo !

In the last two fiqures, it should read

V1 = 3/4 E, not 3/4 CE

Bob Sciamanda
Physics, Edinboro Univ of PA (Em)
trebor@winbeam.com
http://www.winbeam.com/~trebor/
----- Original Message ----- 
From: "Brian Whatcott" <betwys1@sbcglobal.net>
To: "Forum for Physics Educators" <phys-l@carnot.physics.buffalo.edu>
Sent: Saturday, March 29, 2008 2:15 PM
Subject: Re: [Phys-l] Capacitance problem


> At 10:32 AM 3/29/2008, Bob S., you wrote:
> > I have taken a different approach, concentrating on the CHARGE on each
> > capacitor plate.  For simplicity I assume ideal capacitors (no fringing), 
> > of
> > equal value.  Once the EMF is disconnected, the charge +Q is trapped on 
> > the
> > upper plate of C1.  For an ideal capacitor, a charge -Q will be attracted
> > onto the lower plate of C1 from wherever it is available.  Grounding this
> > lower plate does not affect this charge value, and the potential across C1
> > is still 1/2 the original EMF, but it does lower the point V2 to ground
> > potential.
> >
> > See some sketrches at:
> >
> > http://www.winbeam.com/~trebor/CAPS/CAPS.jpg
> >
> > Bob Sciamanda
>
>
> I understand that the original question was not addressed to the first 
> cycle
>  of operation, - but to the result of numerous cycles.
>
>  Does it seem to you that the upper capacitor ends
> up with the battery potential across its plates?
>
>
>
> Brian Whatcott    Altus OK    Eureka!
>
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