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Re: [Phys-l] Collision of irregular bodies



In the absence of tangential effects (friction or an equivilent) wouldn't any forces have to act perpendicularly to the surfaces at the point of contact? I'm assuming that this is what is intended by the term "action reaction pair". I suppose this would be problematic if one "surface" consisted of an infinitely sharp point, but otherwise I'm not sure how the force directions can be different?

----- Original Message ----- From: "John Denker" <jsd@av8n.com>
To: "Forum for Physics Educators" <phys-l@carnot.physics.buffalo.edu>
Sent: Friday, August 11, 2006 5:50 PM
Subject: Re: [Phys-l] Collision of irregular bodies


D.V.N.Sarma wrote:

When two bodies of smooth surface but irregular shape collide
what is the line along which the action reaction pair acts?

Short answer: Nobody knows, not without significantly more
information. Even in the absence of friction (which may or
may not be what was intended by saying "smooth surface")
the outcome depends on details such as the distribution of
mass within the objects.

And I'm not even sure the question makes sense.

In such a collision, you need to know two things: how
much momentum is transferred, and how much angular
momentum is transferred. I suppose you could define a
"line of action" but I'm not sure it would tell you
what you really want to know about the collision.

==========

This has serious practical consequences. Suppose for
instance you are chopping down a tree that stands close
to the north side of a house. Even assuming you arrange
that the top of the tree falls northward away from the
house, the tree will have a pronounced tendency to
pivot around its center of mass, which means the base
of the tree could very easily end up considerably south
of the stump, destroying the house.

Of course proper tree-felling technique will prevent
this from happening, but you reeeally want to use the
proper technique. Don't try it unless you're sure you
know how.

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