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BYes it looks good. However, as one author wrote (paraphrased)
those who
do Chi by eye deserve what they get.
So I tried Pearson's test w/ 42 intervals (single day) and m the
claimed
0.274/day. I should have stopped there, as there are only three
classes
(0, 1, & 2) should be at least 5. Anyway, I found Chi square =
0.52 w/
one deg. of freedom. Using the fig. in Evans (p.776) p= ~ 0.5 i.e.
good agreement w/ Poisson distrib. However, I did violate the
condition.
So I tried three day intervals. This time the data looked bad!,
and Chi
square = 13 w/ three degs. of freedom. p = ~ 0.01 rather unlikely
agreement w/ Poisson distrib. Requirement still not fulfilled, but
more
nearly so.
So "went to" Leigh's reference for more data. Nope. Then I turned
the
page in Evans and found "An Extension of the Chi-square Test" cutting
to the chase, only n need be > 5 (it's 42), and I obtained p ~ 0.2
Again a bit ambiguous as it should be between 0.3 and 0.4
Evidently I've gone wrong; where?
bc, not a statistician