Chronology Current Month Current Thread Current Date
[Year List] [Month List (current year)] [Date Index] [Thread Index] [Thread Prev] [Thread Next] [Date Prev] [Date Next]

[Phys-L] Re: A "simple" physics problem?



Simple? My kind of puzzle!

The ice cube initially displaces a volume of water equal in weight
to the weighted ice-cube.

When the cube melts, the shot drops to the bottom, and the shot now
displaces only the shot's leaden volume of water.

No water is now displaced in holding up the shot, so the water level drops.

The reduction of volume indicated by the fall in water level
is calculated from
A - the initial water volume alone
plus
B - the volume of water contained by the ice-cube
plus
C - a volume of ice which displaces the weight of water equal
to the weight of the shot

BEFORE: volume A + B + C

AFTER A + B + D - the volume of the shot.

The volume change which is indicated by the fall in water level is then
C - D

This is visualized more easily by imagining a volume of leaded
ice which is exactly awash with the water surface.

Brian Whatcott Altus OK


At 08:33 PM 4/7/2005, Herbert H Gottlieb wrote:
Here's a simple physics problem that I'm having a bit of difficulty
answering. I would appreciate an answer together with your
reasoning:

An ice cube containing small pieces of lead shot is floating
in a cup of warm water. What will happen to the water level
as the ice cube melts?

Thanks in advance.

Herb Gottlieb from New YOrk City


Brian Whatcott Altus OK Eureka!
_______________________________________________
Phys-L mailing list
Phys-L@electron.physics.buffalo.edu
https://www.physics.buffalo.edu/mailman/listinfo/phys-l